Level 2 Percentage Problem

Level 2 Percentages Problem

In the awadh school gomti nagar, there are 500 students 60% of the students are boys, 40% of whom play hockey and the girls don’t play hockey, 75% of girls play badminton. There are only two games to be played. The number of students who don’t play any game is:

Solution:

Total students = 100

Boys = 60    &  Girls = 40

Boys => Hockey = 24  & Badminton ( don’t know about badminton)

Girls => Badminton = 30  & Hockey = 0

Since we do not have information that whether the rest of the boys playing badminton or not. So we can not determine the total no. of students who are not playing any of the two games.

A fraction in reduced from is such that when it is squared and then its numerator is increased by 25% and the denominator is reduced to 80% it results in 5/8 of the original fraction. The product of the numerator and denominator is:

a)      6          b) 12    c) 10    d)7

Solution:

Go through option. Let us assume option (C)

10= 2 x 5 = 5 x 2 = 1 x 10 x 10 x 1

Consider the proper fraction = 2/5

Since the given percentage value are 25% and 20% that’s why we have picked up option C

2/5 = 4/25 = 5/20

2/5 x 5/8 = 1/4= 5/20

Hence presumed option is correct.

In the chidambaram’s family the ratio of expenses to the savings is 5:3. But his expenses is increased by 60% and income increases by only 25% thus there is a deficit of rs.3500 in the savings. The increased income of Mr. Chidambaram’s is:

Solution:

Income = expenditure + savings

8 x = 5x + 3x   => 1

10x = 8x + 2x  => 2 ( equation 1 = -x to get equation 2)

Now the deficit = (3x – 2x) = x = 3500

And therefore the new salary = 10x = 35,000

In this presidency college two candidates contested a presidential election. 15% of the voters did not vote and 41 votes were invalid. The elected contestant got 314 votes more than the other candidate. If the elected candidate got 45% of the total eligible votes, which is equal to the no. of all the students of the college. The individual votes of each candidate are:

a       a)      2250 and 1936       b) 3568 and 3254    c) 2442 and 2128       d)2457 and 2143

Solution:

Go through options

2457 – 2143 = 314

Again ( 2457 + 2143 ) + 41 = 4641

Now  4641/0.85 = 5460

Again   5460 x 45 /100 = 2457

Hence the presumed option is correct

The annual earning of mr.sekar is rs. 4 lakhs per annum for the first year of his job and his expenditure was 50% later on for the next 3 years his average income increases by rs.40,000 per annum and the saving was 40%, 30% and 20% of the income. What is the percentage of his total savings over the total expenditure if there is no any interest is applied on the savings for these four years:

Solution:

Income => 4    4.4       4.8       5.2]      18.4     lakh

Saving => 2     1.76     1.44     1.04]    6.24     lakh

Exp =>    2      2.64     3.36     4.16]    12.16   lakh

So,       6.24/12.16 x 100 = 51 6/19%