Relation
between Efficiency
In this case the
efficiency of different persons are different but when they work in a group,
so the efficiency of the group is required to know the time taken. For example
3 men can do a work in 4 days while 12 boys can do the same work in 3 days. It
means we need 3 x 4 = 12 man – days i.e., 12 men can finish the job in 1 day.
Similarly we need 12 x
3 = 36 boys days i.e., 36 boys can finish the same job in 1 day.
Here we can see that to
finish the work in only 1 day 12 men are needed while 36 boys are needed. Thus
we can conclude that work of 12 men is equal to the work of 36 boys. Therefore
efficiency of 12 men is equal to 36 boys i.e., we can say the efficiency of 1
man is equal to 3 boys. Thus a man is thrice efficient as a boy or we can say
that a man is two times more efficient than a boy.
Problem:
6
boys and 8 women finish a job in 6 days and 14 boys and 10 women finish the
same job in 4 days. In how many days working together 1 boy and 1 woman can
finish the work?
Solution:
In this kind of
question we find the work force required to complete the work in 1 day (or
given unit of time) then we equate the work force to find the relationship
between the efficiencies (or work rate) between the different workers.
Therefore 6B + 8W = 6
days
= 6 (6B + 8W) = 1 day (Inversely
proportional)
= 36B + 48W = 1
Again 14B + 10 W = 4
days
56B +40W =1
So, here it is clear
that either we employ 36B and 48W to finish the work in 1 day or 56B and 40W to
finish the same job in 1 day. Thus we can say
= 36B+48W = 56B+40W
20B =8W
W = 2.5B
Thus a woman is 2.5
times as efficient as a boy
Now since 36B + 48W =1
36B +48 X (2.5B) =1
156B =1
i.e. to finish the job
in 1 day 156 boys are required or the amount of work is 156 boys-days
again 1W+1B = 2.5B + 1B
= 3.5B
Now. Since 156 boys can
finish the job in 1 day
So 1 boy can finish the
job in 1 X 156 days
Therefore 3.5boys can
finish the job in 1 X156/3.5 = 44 4/7 days
6
men and 8 women can do a job in 10 days. In how many days can men and 9 women
do the same job?
Solution:
Since we don’t know the
relation between work rate ( or efficiency) between a man and that of a women
so we cant find the required number of days.
6
men and 8 women can do a job in 10 days. In how many days can 3 men and 4 women
finish the same job working together?
Solution:
Notice here we don’t know
the relation of efficiencies but we can solve the problem due to clear relation
between the work force.
Since 6M + 8W = 10 days
2(3M + 4W) = 10 days
= (3M+4W) = 20 days
Since, the work force
has become half of the original force so number of days must be double
Thus required number of
days = 20
Thank you
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